A) \[{{[Zn\,{{(N{{H}_{3}})}_{6}}]}^{2+}}\]
B) \[{{[Ni\,{{(N{{H}_{3}})}_{6}}]}^{2+}}\]
C) \[{{[Cr\,{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
D) \[{{[Co\,{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
Correct Answer: D
Solution :
| [a] Because of \[3{{d}^{10}}\] configuration no \[(n-1)\]d orbital is available for \[{{d}^{2}}s{{p}^{3}}\] hybridisation and thus forms outer orbital complex. The complex is diamagnetic. |
| [b] Because of \[3{{d}^{8}}\] configuration no \[(n-1)\]d orbital is available for \[{{d}^{2}}s{{p}^{3}}\] hybridisation and thus forms outer orbital complex. The complex is paramagnetic with two unpaired electrons. |
| [c] The complex is inner orbital complex but \[3{{d}^{.3}}\] configuration has three unpaired electrons with weak as well as with strong field ligand. |
| [d] In the diamagnetic octahedral complex, \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}},\] the cobalt ion is in +3 oxidation state and has the electronic configuration represented as shown below. |
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