A) \[(-\infty ,\,\,2)\]
B) (2, 3)
C) \[(6,\,\,\infty )\]
D) (4, 6)
Correct Answer: D
Solution :
Clearly a >1 |
\[{{b}^{2}}-10b+25>1\] |
\[{{b}^{2}}-10b+24>0\] |
\[b\in (-\,\infty ,\,\,4)\cup (6,\,\,\infty )\] |
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