A) \[N{{H}_{3}},\]\[C{{r}_{2}}{{O}_{3}}\] and \[{{H}_{2}}O.\]
B) \[{{N}_{2}}\]\[C{{r}_{2}}{{O}_{3}}\] and\[{{H}_{2}}O.\]
C) \[N{{O}_{2}},\]\[Cr{{O}_{3}}\]and \[{{H}_{2}}O.\]
D) \[{{N}_{2}}O,\]\[C{{r}_{2}}{{O}_{3}}\]and \[{{H}_{2}}O.\]
Correct Answer: B
Solution :
\[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\xrightarrow{{}}{{N}_{2}}+C{{r}_{2}}{{O}_{3}}+4{{H}_{2}}O\]
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