A) 96 sq. cm
B) 84 sq. cm
C) 72 sq. cm
D) 60 sq. cm
Correct Answer: C
Solution :
Produce the median AM to D such that |
GM=MD |
And join to B and C. |
Now GBDC is a parallelogram. Note that the sides \[\Delta GDC\] of the are 6,8,10 |
\[\Rightarrow \angle GDC=90{}^\circ \] |
\[\left. \begin{matrix} Area\,\,of\,\,\Delta \,ADC=\frac{12.8}{2}=48 \\ Area\,\,of\,\,\Delta \,MDC=\frac{3.8}{2}=12 \\ \end{matrix} \right]\]\[\Rightarrow Area\,\,of\,\,\Delta \,AMC=36\]\[\Rightarrow Area\,\,of\,\,\Delta \,ABC=72\,c{{m}^{2}}]\] |
You need to login to perform this action.
You will be redirected in
3 sec