A) \[x=\frac{n\pi }{2},n\in Z\]
B) \[x=n\pi ,\,\,n\in Z\]
C) \[x=(2n+1)\pi ,n\in Z\]
D) none of these
Correct Answer: B
Solution :
we have, than |
\[\Rightarrow 5x-n\pi +3x,n\in Z\Rightarrow x=\frac{n\pi }{2},n\in Z\] |
If n is odd, then \[x=\frac{n\pi }{2}\] gives extraneous solutions. Thus, the solution of the gives equation will be given by \[x=\frac{n\pi }{2},\] where n is even, say \[n=2m,\] \[m\in Z\]. Hence the required solution is \[x=m\pi ,\]\[m\in Z\] |
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