A) 0.12
B) 0.26
C) 1.2
D) 0.37
Correct Answer: B
Solution :
\[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}={{\left( \frac{1}{2} \right)}^{1/3}}=\frac{1}{1.26}\] |
Also \[\frac{N}{{{N}_{0}}}=\frac{1}{1.26}\Rightarrow \frac{{{N}_{u}}}{{{N}_{Pb}}+{{N}_{0}}}=\frac{1}{2.26}\]\[\Rightarrow \]\[{{N}_{Pb}}=0.26{{N}_{0}}\Rightarrow \frac{{{N}_{Pb}}}{{{N}_{0}}}=0.26\] |
You need to login to perform this action.
You will be redirected in
3 sec