A) 1
B) 0
C) \[4-\sin 4\]
D) None
Correct Answer: B
Solution :
\[f(-x)=\frac{{{\sin }^{2}}x}{[-x/\pi ]+1/2}=\frac{{{\sin }^{2}}x}{-1-[x/\pi ]+1/2}\] |
\[f(-\,x)=\frac{{{\sin }^{2}}x}{1/2+[x/\pi ]}=-\,f(x)\] |
odd function \[\therefore \,\,Ans.=0\] |
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