The displacement of a particle starting from rest and moving with constant acceleration is calculated by the formula \[s=\frac{1}{2}a{{t}^{2}}\] . If there occurs an error of 10% in the measurement of time then the error in the calculation of \[s\]is: |
A) \[10%\]
B) \[19%\]
C) \[20%\]
D) \[21%\]
Correct Answer: D
Solution :
\[\sigma \frac{1}{2}a{{\left( 1.1t \right)}^{2}}\] |
\[{{S}^{1}}=1.21\left( \frac{1}{2}a{{t}^{2}} \right)=1.21s\] |
\[\therefore \]\[\frac{\Delta s}{s}\times 100=21%\] |
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