Two plane mirrors \[{{M}_{1}}\] and \[{{M}_{2}}\] each have length 2 m and are separated from one another by 1 cm. A ray of light is incident at one end of mirror \[{{M}_{1}}\] at angle\[45{}^\circ \]. How many reflections the ray will Suffer before going out from the other end? : |
A) 100
B) 200
C) 101
D) 201
Correct Answer: D
Solution :
distance occupied in one reflection, |
\[x=\frac{1}{\sin 45{}^\circ }=2cm\] |
So total number of reflections on\[{{M}_{2}}\], |
\[\frac{200}{2}=100\] |
Total number of reflection on \[{{M}_{1}}=101.\] |
\[\therefore \]\[N=100+101=201.\] |
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