A) 80%, +2.7 unit
B) 20%, -27 unit
C) 20%, +2.7 unit
D) 80%, -27 unit
Correct Answer: C
Solution :
[C] Enantiomeric excess \[=\frac{Excess\,\,of\,\,one\,\,enantiomer\,\,over\,\,other}{Entire\,\,mixture}\times 100\] \[=\frac{6-4}{6+4}\times 100=20\]%You need to login to perform this action.
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