A) 2 and 1
B) \[-\,2\,\,\text{and}\,-\,1\]
C) \[-\,2\,\,\text{and}\,\,1\]
D) \[2\,\,\text{and}\,\,-1\]
Correct Answer: A
Solution :
[a]We have, |
\[A=2\hat{i}-\hat{j}+\hat{k},\]\[B=\hat{i}-3\hat{j}-5\hat{k},\]\[C=a\hat{i}-3\hat{j}+\hat{k}\] |
\[CA=(2-a)\hat{i}+2\hat{j}\] |
\[CB=(1-a)\hat{i}-6\hat{k}\] |
\[CA\cdot CB=0\] |
\[\therefore \]\[(2-a)(1-a)=0\] |
\[a=2,1\] |
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