A) \[\frac{1}{14}\]
B) \[\frac{1}{7}\]
C) \[\frac{5}{14}\]
D) \[\frac{1}{50}\]
Correct Answer: A
Solution :
[a]A = Events that sum of digits on selected ticket is 8. |
\[A=\{08,17,26,35,44\}\] |
\[n\,(A)=5\,P(A)=\frac{5}{50}\] |
B = Events that product of digits is zero |
B= {00, 01,..., 10, 20, 30, 40} |
\[n\,(B)=14,\]\[P\,(B)=\frac{14}{50}\] |
\[A\cap B=\{08\}\] |
\[n\,(A\cap B)=1P\,(A\cap B)=\frac{1}{50}\] |
Required probability \[P\left( \frac{A}{B} \right)=\frac{P(A\cap B)}{P\,(B)}\] |
\[=\frac{1/50}{14/50}=\frac{1}{4}\] |
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