KVPY Sample Paper KVPY Stream-SX Model Paper-20

  • question_answer
     Among the following complexes (K-P)
    \[{{K}_{3}}[Fe{{(CN)}_{6}}](\mathbf{K}),[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}(\mathbf{L}),\]
    \[N{{a}_{3}}[Co{{(oxalate)}_{3}}](\mathbf{M}),[Ni{{({{H}_{2}}O)}_{6}}]C{{l}_{2}}(\mathbf{N})\]
    \[{{K}_{2}}[Pt{{(CN)}_{4}}](O)\]and\[[Zb{{({{H}_{2}}O)}_{6}}]{{(N{{O}_{3}})}_{2}}(\mathbf{P})\]
    the diamagnetic complexes are

    A) K, L, M, N

    B) K, M, O, P

    C) L, M, O, P

    D) L, M, N, O

    Correct Answer: C

    Solution :

    Complex No. of electrons in outer\[d\]orbital No. of unpaired electron (s)
    \[{{[Fe{{(CN)}_{6}}]}^{3-}}\] \[3{{d}^{5}}\] 1(\[{{\operatorname{CN}}^{-}}\]causes pairing of electrons)
    \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\] \[3{{d}^{6}}\] 0
    \[{{[Co{{(ox.)}_{3}}]}^{3-}}\] \[3{{d}^{6}}\] 0
    \[{{[Ni{{({{H}_{2}}O)}_{6}}]}^{2+}}\] \[3{{d}^{8}}\] 2
    \[{{[Pt{{(CN)}_{4}}]}^{2-}}\] \[5{{d}^{8}}\] 0(\[{{\operatorname{CN}}^{-}}\]causes pairing of electrons)
    \[{{[Zn{{({{H}_{2}}O)}_{6}}]}^{2+}}\] \[3{{d}^{10}}\] 0
    Thus, L, M, O and P are diamagnetic.


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