In the reaction, |
\[P+Q\xrightarrow{{}}R+S\] |
The time taken for \[75%\] reaction of P is twice the time taken for \[50%\] reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is |
A) 2
B) 3
C) 0
D) 1
Correct Answer: D
Solution :
For P, if \[{{\operatorname{t}}_{50%}}=x\]then\[{{t}_{75%}}=2\operatorname{x}\] |
This is true only for first order reaction. |
So, order with respect to P is 1. |
Further the graph shows that concentration of Q decreases with time. So rate, with respect to Q, remains constant. Hence, it is zero order wrt Q. |
So, overall order is \[1+0=1\] |
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