A) Reaction of \[{{H}_{2}}S{{O}_{4}}\]with \[NaOH.\]
B) Production of ozone from oxygen in the atmosphere by lightening.
C) Production of nitrogen oxides from nitrogen and oxygen in the atmosphere by lightening.
D) Evaporation of water.
Correct Answer: C
Solution :
| \[2NaOH+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}N{{a}_{2}}S{{O}_{4}}+2{{H}_{2}}O\] |
| It is neutralization, not redox reaction. |
| \[3{{\overset{0}{\mathop{O}}\,}_{2}}\xrightarrow{Light}2{{\overset{0}{\mathop{O}}\,}_{3}}\] |
| It is not a not redox reaction since it does not involue oxidation or reduction. |
| \[{{\overset{0}{\mathop{N}}\,}_{2}}+{{\overset{0}{\mathop{O}}\,}_{2}}\xrightarrow{Light}2\overset{+2-2}{\mathop{NO}}\,\] |
| Here oxidation of \[{{\operatorname{N}}_{2}}\]and reduction of \[{{\operatorname{O}}_{2}}\] is taking place. It is a redox reaction. |
| \[{{H}_{2}}O\left( 1 \right)\xrightarrow{\Delta }{{H}_{2}}O\left( g \right)\] |
| It is not a redox reaction, since it does not involve oxidation and reduction. |
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