A) 213
B) 426
C) 318
D) 1272
Correct Answer: A
Solution :
In \[P{{H}_{3}}(g),\] energy required to break 3P-H bonds \[=954kJmo{{l}^{-1}}\] |
\[\therefore \]Energy required to break 1P-Hbond \[=\frac{954}{3}=318kJmo{{l}^{-1}}\] |
In \[{{\operatorname{P}}_{2}}{{H}_{4}}\left( g \right),\]energy of 1 P-P bond +4 P-H bonds\[=1485kJmo{{l}^{-1}}\] |
\[\because \]Energy of 1 P- H bond \[=318kJmo{{l}^{-1}}\] |
\[\because \]Energy of 4 P- H bond \[=318\times 4\]\[=1272kJmo{{l}^{-1}}\] |
Thus, the P-P bond energy \[=1485-1272\]\[=213kJmo{{l}^{-1}}\] |
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