A) \[1.24\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
B) \[12.4\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
C) \[124\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
D) \[1240\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
Correct Answer: A
Solution :
Conductivity \[(\kappa )=\frac{l}{R.a.}\] |
When. \[\operatorname{R}=100\Omega \]and \[\kappa =1.29\operatorname{S}\,{{m}^{-1}}\] |
Cell constant. \[\left( \frac{l}{a} \right)=1.29\times 100=129\] |
Now conductivity of 0.02 M solution |
When \[R=520\Omega \] will be |
\[\kappa =\frac{1}{520}\times 129;\,{{\Lambda }_{m}}=\frac{\kappa \times 1000}{M}\]\[=\frac{129}{520}\times \frac{1000}{0.02}=1.24\times {{10}^{-4}}\operatorname{S}\,{{m}^{2}}{{\operatorname{mol}}^{-1}}\] |
You need to login to perform this action.
You will be redirected in
3 sec