question_answer

In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. of these students is selected at random, the probability that the student selected has opted for NCC nor for NSS is:

A) \[\frac{1}{6}\]

B) \[\frac{1}{3}\]

C) \[\frac{2}{3}\]

D) \[\frac{5}{6}\]

Correct Answer: A

Solution :

\[A\to \] opted NCC;  \[B\to \] opted NSS

\[\therefore \]P (neither A nor B)\[=\frac{10}{60}=\frac{1}{6}.\]