A) \[1.24\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
B) \[12.4\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
C) \[124\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
D) \[1240\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
Correct Answer: A
Solution :
| Conductivity \[(\kappa )=\frac{l}{R.a.}\] |
| When. \[\operatorname{R}=100\Omega \]and \[\kappa =1.29\operatorname{S}\,{{m}^{-1}}\] |
| Cell constant. \[\left( \frac{l}{a} \right)=1.29\times 100=129\] |
| Now conductivity of 0.02 M solution |
| When \[R=520\Omega \] will be |
| \[\kappa =\frac{1}{520}\times 129;\,{{\Lambda }_{m}}=\frac{\kappa \times 1000}{M}\]\[=\frac{129}{520}\times \frac{1000}{0.02}=1.24\times {{10}^{-4}}\operatorname{S}\,{{m}^{2}}{{\operatorname{mol}}^{-1}}\] |
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