A) \[\frac{1}{6}\]
B) \[\frac{1}{3}\]
C) \[\frac{2}{3}\]
D) \[\frac{5}{6}\]
Correct Answer: A
Solution :
\[A\to \] opted NCC; \[B\to \] opted NSS |
\[\therefore \]P (neither A nor B)\[=\frac{10}{60}=\frac{1}{6}.\] |
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