A) Estimating the concentration of iron
B) Measuring the concentration of CN
C) Measuring the solid state magnetic moment
D) Thermally decomposing the compound.
Correct Answer: C
Solution :
The magnetic moment \[(\mu )\] of a species is related to its number of unpaired electrons (n) in form of following expressions. |
\[\mu =\sqrt{n(n+2)}B.M\] |
The number of unpaired electrons in the given pairs are as follows: |
\[F{{e}^{2+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{6}}\] |
Or |
Thus, \[n=4.\] |
\[F{{e}^{3+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{5}}\] |
Or |
Thus, \[n=5.\] |
\[\overset{+}{\mathop{N}}\,O\]or \[\overset{+}{\mathop{{\underset{\scriptscriptstyle\centerdot\centerdot}{N}}}}\,=\ddot{O}:\] \[n=0\] |
NO or \[:\dot{N}=\ddot{O}:\] \[n=1\] |
The given combinations differ in the number of unpaired electrons. Hence these can be differentiated by the measurement on the solid state magnetic moment of nitroprusside ion. |
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