Both the inductors and the cell are ideal. Find the current (in Amperes) in 2H inductance in steady state. |
A) Zero
B) 1A
C) 2A
D) 3A
Correct Answer: D
Solution :
In steady state current from battery \[=\frac{10}{5}=5A\] |
In parallel inductors \[{{L}_{1}}{{I}_{1}}={{L}_{2}}{{I}_{2}}\] all the time |
\[\Rightarrow {{i}_{1}}=\frac{{{L}_{2}}}{{{L}_{1}}+{{L}_{2}}}i=\frac{3}{3+2}\times 5=3A\] |
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