A) 39
B) 40
C) 59
D) 60
Correct Answer: B
Solution :
Using Mosely?s law for both cobalt and impurity \[\sqrt{f}=K\,\,(Z-1)\Rightarrow \sqrt{\frac{c}{\lambda }}=K\,\,(Z-1)\]\[\Rightarrow \sqrt{\frac{c}{{{\lambda }_{co}}}}=K({{Z}_{co}}-1)\]and \[\sqrt{\frac{c}{{{\lambda }_{x}}}}=K({{Z}_{x}}-1)\]\[\Rightarrow \sqrt{\frac{{{\lambda }_{co}}}{c}}=\frac{{{Z}_{x}}-1}{{{Z}_{co}}-1}={{Z}_{x}}=40\]You need to login to perform this action.
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