A block of mass m is pushed across a rough surface by an applied force F, directed at an angle \[\theta \] relative to the horizontal as shown. The block experiences a friction force \[f\] in the opposite direction. What is the coefficient of friction between the block and the surface? |
A) \[\frac{mg}{F\,\,\sin \phi }\]
B) \[\frac{f}{F\,\,\sin \phi +mg}\]
C) \[\frac{f}{mg}\]
D) \[\frac{mg}{f}\]
Correct Answer: B
Solution :
the key to finding the coefficient of friction \[\mu \]is in calculating the correct normal force acting on the block |
\[\sum{Fy=m{{a}_{y}}}\] |
Free body diagram |
Block does not move in y direction |
\[\therefore {{a}_{y}}=0\] |
\[\therefore N=F\sin \phi +mg\] |
\[\mu =\frac{{{F}_{friction}}}{N}=\frac{f}{F\sin \phi +mg}\] |
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