A) \[\frac{T}{\sqrt{6}}\]
B) \[\frac{T}{6}\]
C) \[\sqrt{6}T\]
D) 36T
Correct Answer: C
Solution :
The length of the pendulum hasn?t changed and the only other factor that determines the period of a pendulum is the acceleration due to gravity |
\[T=2\pi \sqrt{\frac{\ell }{g}}\] |
\[T=2\pi \sqrt{\frac{\ell }{\frac{1}{6g}}}\] |
\[T=\sqrt{6}\left( 2\pi \sqrt{\frac{\ell }{g}} \right)\] |
\[T=\sqrt{6}\,\,T\] |
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