A) 3
B) 2
C) 1
D) none of these
Correct Answer: B
Solution :
Let \[D=\left| \begin{matrix} {{a}_{11}} & {{a}_{12}} & {{a}_{13}} \\ {{a}_{21}} & {{a}_{22}} & {{a}_{23}} \\ {{a}_{31}} & {{a}_{32}} & {{a}_{33}} \\ \end{matrix} \right|\] |
for maximum value we have to assign maximum value to the +ve term & minimum value to \[ve\]term which is possible if three elements will become zero of different row & different column. |
\[\therefore \] i.e. \[{{a}_{13}}={{a}_{21}}={{a}_{32}}=0\]& \[{{a}_{11}}={{a}_{32}}={{a}_{33}}={{a}_{12}}\] |
\[\therefore \] \[{{D}_{\max }}=2-0=2\] |
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