A) 1
B) 2
C) 4
D) none of these
Correct Answer: B
Solution :
\[f\,(1)=p-q+r=-1\] | ?(i) |
\[f\,(0)=r>0\] | ?(ii) |
\[f\,(2)=4p-2q+r>0\] | ?(iii) |
(ii) + (iii) \[\Rightarrow \]\[4p-2q+2r>0\] | |
\[2p-q+r>0\] | |
\[p+(p-q+r)>0\] [using (i)] | |
\[p-1>0\] \[\Rightarrow \]\[p>1\] | |
\[\therefore \] \[p=2\] \[(\because p\in N)\] |
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