• # question_answer  If the de Brogile wavelength of the electro in nth Bohr orbit in a hydrogenic atom is equal to $1.5\pi {{a}_{0}}$($a{{ }_{0}}$ is Bohr radius), then the value of n/z. is; A) 0.40 B) 1.50 C) 1.0 D) 0.75

 $2\pi r=n\lambda$ $\lambda =\frac{2\pi r}{n}=\frac{2\pi {{n}^{2}}{{a}_{0}}}{n\times Z}=2\pi \frac{n}{Z}{{a}_{0}}$ $\lambda =1.5\pi {{\alpha }_{0}}$ $\therefore$      $2\pi \frac{n}{Z}{{a}_{0}}=1.5\pi {{\alpha }_{0}}$$\Rightarrow$            $\frac{n}{Z}=\frac{1.5}{2}=0.75.$