A) 2.5 amp
B) 2 amp
C) 5/6 amp
D) 5/3 amp
Correct Answer: A
Solution :
After long time induced emf in L become zero so, L is replaced with simple conducting wire. So new equivalent circuit is shown. |
\[{{I}_{1}}=\frac{E}{{{R}_{eq}}}\] |
\[{{R}_{eq}}=2+{{R}_{eq}}\] of 6 &\[3\Omega =2+\frac{6\times 3}{6+3}=2+2=4\] |
\[{{I}_{1}}=\frac{10}{4}=2.5\,\,amp\] |
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