A) \[-1\]
B) 0
C) 1
D) does not exist
Correct Answer: B
Solution :
\[f\,(x)=\,\,|x{{|}^{3}}\] |
\[\therefore \] \[f'\,(x)=\left\{ \begin{matrix} 3|x{{|}^{2}}\cdot \frac{x}{|x|} & x\ne 0 \\ 0 & x=0 \\ \end{matrix} \right.\] |
You need to login to perform this action.
You will be redirected in
3 sec