A) 2
B) \[-\,2\]
C) 0
D) 1
Correct Answer: B
Solution :
\[x-y=2\] |
\[x+y+xy\] is to be minimized. |
Putting \[y=x-2.\] |
we get, \[f\,(x)=2x-2+x\,(x-2)\] |
\[f'\,(x)=2+2x-2=0\] at \[x=0.\] |
\[f''\,(x)=2\]\[\Rightarrow \]\[x=0\] is a |
point of minima |
Thus minimum value is at \[x=0\] & \[y=-\,2.\] |
Hence [B] is correct. |
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