A) (4/3)
B) \[(\sqrt{3}+1)/1\]
C) \[\left( \frac{\sqrt{3}+1}{\sqrt{3}-1} \right)\]
D) \[\sqrt{3}/1\]
Correct Answer: D
Solution :
For tangent galvanometer \[\frac{\mu NI}{2R}={{B}_{H}}\tan \theta \] |
\[\therefore \,\,\frac{{{N}_{1}}}{{{N}_{2}}}=\frac{\tan {{\theta }_{1}}}{\tan {{\theta }_{2}}}\Rightarrow \frac{{{N}_{1}}}{{{N}_{2}}}=\frac{\tan 60{}^\circ }{\tan 45{}^\circ }=\frac{\sqrt{3}}{1}\] |
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