KVPY Sample Paper KVPY Stream-SX Model Paper-21

  • question_answer
    If 20J of energy is trapped at producer level, then how much energy will be available to peacock as food in the following chain?
    Plant \[\to \]Mice\[\to \]Snake\[\to \]Peacock

    A) 0.02 J

    B) 0.002 J

    C) 0.2 J    

    D) 0.0002 J

    Correct Answer: A

    Solution :

    According to 10% law of energy flow by Lindemann,
    Plant \[\to \]\[20J\]
    Mice \[\to \]\[20\times 10%=2\,J\]
    Snake \[\to \] \[2\times 10%=0.2\,J\]
    Peacock\[\to \]\[0.2\times 10%=0.02\,J\]

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