• # question_answer The oscillations represented by curve 1 in the graph are expressed by equation $x\text{ }=\text{ }A\text{ }sin\omega t.$The equation for the oscillations represented by curve 2 is expressed as - A) $x=2A\,\sin \,\,(\omega t-\pi /2)$ B) $x=2A\,\sin \,\,(\omega t+\pi /2)$ C) $x=-\,2A\,\sin \,\,(\omega t-\pi /2)$ D) $x=A\sin \,\,(\omega t-\pi /2)$

Oscillations represented by curve 2 lags in phase by $\pi /2$ and the periods are same. Amplitude of curve 2 is double that of 1.