A circuit is arranged as shown. At time \[\operatorname{t}=0 s,\] switch S is placed in position 1. At t= 5 s, contact is changed from 1 to 2. The voltage across the capacitor is measured at t = 5 s, and at t = 6 s. Let these voltages be \[{{\operatorname{V}}_{1}}\] and \[{{\operatorname{V}}_{2}}\] respectively. Then \[{{\operatorname{V}}_{1}}\] and \[{{\operatorname{V}}_{2}}\] respectively are |
A) 10 volt and 0 volt
B) 9.18 volt and 3.67 volt
C) 9.18 volt and 3.37 volt
D) 10 volt and 3.67 volt
Correct Answer: C
Solution :
(i) \[V={{V}_{0}}\left( 1-{{e}^{-\frac{t}{2RC}}} \right);\] |
\[V={{V}_{0}}\left( 1-{{e}^{-\frac{5}{2}}} \right)=9.18volt\] |
\[V={{V}_{0}}\left( {{e}^{-\frac{t}{RC}}} \right)=9.18{{e}^{-1/1}}\] |
\[=\frac{9.18}{e}=3.37\,volt\] |
You need to login to perform this action.
You will be redirected in
3 sec