A conducting loop is being pulled with speed \[v\] from region I of magnetic field to region II. If resistance of the loop is \[R\], current induced in the loop at the instant shown is |
A) \[\frac{{{B}_{0}}\ell v}{R},\]Clockwise
B) \[\frac{{{B}_{0}}\ell v}{R},\]anticlockwise
C) \[\frac{3{{B}_{0}}\ell v}{R},\]clockwise
D) \[\frac{3{{B}_{0}}\ell v}{R},\]anticlockwise
Correct Answer: C
Solution :
\[e={{e}_{1}}+{{e}_{2}}\] |
\[={{B}_{0}}v\ell +2{{B}_{0}}v\ell \] |
\[=3{{B}_{0}}v\ell \] |
\[\therefore \] \[i=\frac{e}{R}=\frac{3{{B}_{0}}v\ell }{R}\] |
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