A) 0.36(AA); 0.48 (Aa); 0.16 (aa)
B) 0.16(AA); 0.24 (Aa); 0.36 (aa)
C) 0.16(AA); 0.48 (Aa); 0.36 (aa)
D) 0.16(AA); 0.36 (Aa); 0.48 (aa)
Correct Answer: C
Solution :
Frequency of dominant allele (say p) = 0.4 |
Frequency of recessive allele (say q) \[=1-0.4=0.6\] |
\[\therefore \] Frequency of homozygous dominant individuals (AA) \[={{p}^{2}}={{(0.4)}^{2}}=0.16\] |
Frequency of heterozygous individuals (Aa) \[=2pq=2(0.4)(0.6)=0.48\] |
Frequency of homozygous recessive individuals (aa) |
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