A) \[{{s}^{4}}\]
B) \[{{b}^{2}}{{c}^{2}}\]
C) \[{{c}^{2}}{{a}^{2}}\]
D) \[{{a}^{2}}{{b}^{2}}\]
Correct Answer: D
Solution :
\[{{c}^{2}}={{a}^{2}}+{{b}^{2}}\] \[\Rightarrow \]\[\angle \,C=\frac{\pi }{2}\] |
\[\therefore \]\[\Delta =\frac{1}{2}ab\sin C=\frac{1}{2}ab\]\[\Rightarrow \]\[\sqrt{s\,(s-a)\,\,(s-b)\,\,(s-c)}=\frac{1}{2}ab\]\[\Rightarrow \]\[4s\,(s-a)\,\,(s-b)\,\,(s-c)={{a}^{2}}\,{{b}^{2}}.\] |
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