A)
B)
C)
D)
Correct Answer: D
Solution :
Here, reaction (i) is known as Dow's process, where chlorobenzene gets converted into phenol in presence of \[NaOH\]. The formed phenol then reacts with chloroform in aqueous \[NaOH\] to give salicylaldehyde. This reaction is known as Reimer-Tiemann reaction. |
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