A) \[{{[NiC{{l}_{4}}]}^{2-}}\]
B) \[[Cu{{(N{{H}_{3}})}_{4}}]S{{O}_{4}}\]
C) \[{{[CoC{{l}_{6}}]}^{4-}}\]
D) \[{{[CrB{{r}_{6}}]}^{3-}}\]
Correct Answer: D
Solution :
There unpaired electron is present in \[{{(CrB{{r}_{6}})}^{3-}}\] and \[{{(Ni\,\,{{({{H}_{2}}O)}_{6}})}^{2+}}\]Magnetic moment \[=\sqrt{n\,(n+2}=\sqrt{3\,(3+2)}=3.87\]
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