A) \[s{{p}^{3}}\]and \[{{d}^{3}}s{{p}^{2}}\]
B) \[ds{{p}^{2}}\] and \[{{d}^{2}}s{{p}^{3}}\]
C) \[s{{p}^{3}}\] and \[{{d}^{2}}s{{p}^{3}}\]
D) \[ds{{p}^{2}}\] and \[s{{p}^{3}}{{d}^{2}}\]
Correct Answer: C
Solution :
\[Ni\,\,{{(CN)}_{4}}\] \[Ni:[Ar]3{{d}^{8}}4{{s}^{2}}=t_{2g}^{2,2,2}e_{g}^{2,2}\] |
\[C{{N}^{-}}\] is a strong field ligand, hence it will cause pairing of electrons. Hence, \[ds{{p}^{2}}\] |
\[Cr{{({{H}_{2}}O)}_{{{6}^{+2}}}}C{{r}^{2}}:[Ar]3{{d}^{4}}4s{}^\circ \] |
Octahedral complex: \[{{d}^{2}}s{{p}^{3}}\] |
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