A) \[NaOH\]
B) \[conc.\text{ }HCl\]
C) \[{{N}_{2}}\]
D) \[conc.\text{ }HN{{O}_{3}}\]
Correct Answer: D
Solution :
As it becomes passive by the action of conc. \[HN{{O}_{3}}\] forming a protective oxide layer on the surface.
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