A) 20 mA
B) 100 mA
C) 04 mA
D) 63 mA
Correct Answer: A
Solution :
By colour coding. |
\[R=50\times {{10}^{2}}\Omega \] |
\[{{I}^{2}}R=P\] |
\[I=\sqrt{\frac{P}{R}}=20\,mA.\] |
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