A) \[\frac{3F}{2mR}\]
B) \[\frac{F}{3mR}\]
C) \[\frac{F}{2mR}\]
D) \[\frac{2F}{3mR}\]
Correct Answer: D
Solution :
\[F-f=ma\] |
\[fR=\frac{1}{2}m{{R}^{2}}\alpha \] |
\[a=\alpha R.\] |
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