To get output '1' at R, for the given logic gate circuit the input values must be: |
A) X = 0, Y = 1
B) X = 1, Y = 1
C) X = 1, Y = 0
D) X = 0, Y = 0
Correct Answer: C
Solution :
\[R=\overline{P+Q}=\overline{(\overline{x}+y)\overline{(x\overline{y})}}\] |
\[=(\overline{\overline{x}+y}).(x\overline{y})\] |
\[=(x.\overline{y}).(x\overline{y})=x\overline{y}.\] |
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