A) Contains origin
B) is right angle
C) is obtuse
D) none of these
Correct Answer: D
Solution :
\[3x-6y+2z+5=0\] | ??(i) |
\[-\,4x+12y-3z+3=0\] | .?.. (ii) |
\[{{a}_{1}}{{a}_{2}}+{{b}_{1}}{{b}_{1}}+{{c}_{1}}{{c}_{2}}=-12-72-6<0\] | |
hence ?+? sign bisector is origin containing and is also acute angle bisector | |
\[\therefore \frac{3x-6y+2z+5}{7}=\frac{+\,(-\,4x+12y-3z+3}{13}\] | |
\[67x-162y+47z+44=0\] |
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