A) \[(4\sqrt{2},\,\,3)\]
B) \[(8,\,\,3\sqrt{3})\]
C) \[\left( 5,\frac{9}{4} \right)\]
D) \[(16,\,\,3\sqrt{15})\]
Correct Answer: D
Solution :
\[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1\,\,(4\,\sec \theta ,3\tan \theta )\] |
\[\frac{3}{2}\,\,=\,\,\frac{P{{S}_{1}}}{P{{S}_{2}}}\,\,=\left| \frac{\frac{4e\sec \theta +4}{e}}{\frac{4e\sec \theta -4}{e}} \right|=\left| \frac{e\sec \theta +1}{e\sec \theta -1} \right|\]\[\Rightarrow \sec \theta =4\]\[and\,\,\tan \theta =\sqrt{16-1}=\sqrt{15}\] |
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