A) 3
B) 4
C) 5
D) none of these
Correct Answer: B
Solution :
\[x=\frac{p}{p-15}\] | |
\[x=1+\frac{15}{p-15}\] | ?? (1) |
Roots are positive \[\Rightarrow \frac{15}{p-15}>0\]i.e. \[p\in (-\,\infty ,0)\cup (15,\infty )\] But \[p\in N\] | |
\[\therefore p\in (15,\infty )\] | |
From (1), for x to be integer \[\frac{15}{p-15}\]Should be integer, it is possible, When \[0<p-15\le 15\] or \[0<p\le 30\] But \[p>15\] | |
\[\therefore \,\,\,p\in \,\,(15,\,\,\,30]\] So, \[p=16,\,\,18,\,\,20,\,\,30\] | |
\[\therefore \] No. of positive integral roots are 4. |
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