A) \[\mu FR\text{/3}\]
B) \[\mu FR\text{/6}\]
C) \[\mu FR\text{/2}\]
D) \[\frac{2}{3}\mu FR\]
Correct Answer: D
Solution :
\[d\tau =(m\,dN)x\] |
\[=\mu \left( \frac{F}{\pi {{R}^{2}}}\times 2\pi \times dx \right)x\] |
\[\tau =\int\limits_{0}^{R}{d\tau }.\] |
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