A) 18/17
B) 19/18
C) 20/19
D) 21/20
Correct Answer: B
Solution :
\[{{f}_{1}}={{f}_{0}}\left( \frac{340}{340-17} \right)\] |
\[{{f}_{2}}={{f}_{0}}\left( \frac{340}{340-34} \right)\] |
\[\frac{{{f}_{1}}}{{{f}_{2}}}=\frac{306}{323}\]or \[\frac{18\times 17}{19\times 17}\]or\[\frac{18}{19}.\] |
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